19-6x+5x^2=2x+1

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Solution for 19-6x+5x^2=2x+1 equation: 



19-6x+5x^2=2x+1

We move all terms to the left:

19-6x+5x^2-(2x+1)=0

We get rid of parentheses

5x^2-6x-2x-1+19=0

We add all the numbers together, and all the variables

5x^2-8x+18=0

a = 5; b = -8; c = +18;
Δ = b2-4ac
Δ = -82-4·5·18
Δ = -296
Delta is less than zero, so there is no solution for the equation

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